fsck: don't print corse corruption offset
The exact ciphertext block number (4KiB granularity) is already printed in the doRead message. Don't cause confusion by printing the 128KiB-granularity offset as well. doRead 767: corrupt block #4: stupidgcm: message authentication failed fsck: error reading file "pa/d7/d14/f10c" (inum 767): 5=input/output error
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fsck.go
2
fsck.go
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@ -128,7 +128,7 @@ func (ck *fsckObj) file(path string) {
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result, status := f.Read(buf, off)
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result, status := f.Read(buf, off)
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if !status.Ok() {
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if !status.Ok() {
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ck.markCorrupt(path)
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ck.markCorrupt(path)
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fmt.Printf("fsck: error reading file %q (inum %d) at offset %d: %v\n", path, inum(f), off, status)
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fmt.Printf("fsck: error reading file %q (inum %d): %v\n", path, inum(f), status)
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return
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return
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}
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}
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// EOF
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// EOF
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