build.bash: implement "you need Go 1.5" lockout in pure Go
As noticed by @riking, the logic in the bash script will break when Go 1 version numbers reach double-digits. Instead, use a build tag "!go1.5" to cause a syntax error: $ /opt/go1.4.3/bin/go build can't load package: package github.com/rfjakob/gocryptfs: go1.4.go:5:1: expected 'package', found 'STRING' "You need Go 1.5 or higher to compile gocryptfs!" Fixes https://github.com/rfjakob/gocryptfs/issues/133
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build.bash
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build.bash
@ -30,16 +30,6 @@ BUILDTIME=$(date +%s)
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# Make sure we have the go binary
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go version > /dev/null
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# Parse "go version go1.6.2 linux/amd64" to "1.6"
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V=$(go version | cut -d" " -f3 | cut -c3-5)
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# Reject old Go versions already here. It would fail with compile
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# errors anyway.
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if [[ $V == "1.3" || $V == "1.4" ]] ; then
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echo "Error: you need Go 1.5 or higher to compile gocryptfs"
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echo -n "You have: "
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go version
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fi
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LDFLAGS="-X main.GitVersion=$GITVERSION -X main.GitVersionFuse=$GITVERSIONFUSE -X main.BuildTime=$BUILDTIME"
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go build "-ldflags=$LDFLAGS" $@
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